Nuts and Bolts Weight Chart
Mcneil Instruments specializes in the manufacturing and supply of high-quality nuts and bolts for diverse industrial applications. Below is a comprehensive weight chart to help you choose the ideal sizes based on your requirements. Our precision-engineered products ensure durability and reliability in every application.

Nuts and Bolts Weight Chart
Size | Bolt Weight (kg) | Nut Weight (kg) | Total Weight (kg) |
M12 x 35 | 0.049 | 0.013 | 0.062 |
M12 x 40 | 0.053 | 0.013 | 0.066 |
M12 x 45 | 0.058 | 0.013 | 0.071 |
M16 x 35 | 0.087 | 0.032 | 0.119 |
M16 x 40 | 0.094 | 0.032 | 0.126 |
M20 x 45 | 0.173 | 0.061 | 0.234 |
M20 x 50 | 0.186 | 0.061 | 0.247 |
M24 x 45 | 0.258 | 0.104 | 0.362 |
M24 x 50 | 0.276 | 0.104 | 0.380 |
(For a detailed chart, kindly contact Mcneil Instruments.)
Approximate Weight for 100 Pieces
Length (mm) | Diameter (mm) | Approx. Weight (kg) |
12 | M6 | 0.67 |
16 | M8 | 1.59 |
20 | M10 | 3.34 |
25 | M12 | 4.62 |
30 | M14 | 10.12 |
35 | M16 | 15.82 |
40 | M18 | 16.61 |
50 | M20 | 18.25 |
60 | M24 | 19.92 |
(Weights are calculated for bolts with corresponding nuts.)
How to Calculate Weight for Nuts and Bolts
For Bolts
- Determine Dimensions: Measure the bolt’s diameter, length, and thread pitch.
- Material Density: Find the density of the bolt material (e.g., steel, brass, etc.).
- Volume Calculation: Use the formula:
Volume = π × (Radius²) × Length
(For threads, consider a reduced area calculation if precision is needed.) - Weight: Multiply the volume by the material’s density.
Example:
- Bolt Dimensions:
Diameter = 10 mm (Radius = 5 mm), Length = 50 mm - Material Density: Steel = 7.85 g/cm³
- Calculate Volume:
Volume = π × (Radius²) × Length
= 3.1416 × (0.5 cm)² × 5 cm
= 3.1416 × 0.25 × 5 = 3.93 cm³ - Calculate Weight:
Weight = Volume × Density
= 3.93 × 7.85 = 30.85 g
For Nuts
- Measure Dimensions: Determine the outer diameter, inner diameter, and thickness.
- Material Density: Identify the material’s density.
- Volume Calculation: Subtract the inner cylindrical area from the outer area using:
Volume = π × (Outer Radius² – Inner Radius²) × Thickness - Weight: Multiply the volume by the material’s density.
Example:
- Nut Dimensions:
Outer Diameter = 20 mm (Radius = 10 mm),
Inner Diameter = 10 mm (Radius = 5 mm), Thickness = 10 mm - Material Density: Steel = 7.85 g/cm³
- Calculate Volume:
Volume = π × (Outer Radius² – Inner Radius²) × Thickness
= 3.1416 × [(1 cm)² – (0.5 cm)²] × 1 cm
= 3.1416 × (1 – 0.25) × 1
= 3.1416 × 0.75 = 2.36 cm³ - Calculate Weight:
Weight = Volume × Density
= 2.36 × 7.85 = 18.53 g
Why Choose Mcneil Instruments?
- Precision Engineering: Manufactured to exact specifications for superior performance.
- Durability: High-quality materials ensure long-lasting use.
- Custom Sizes: Available in standard and custom specifications.
- Global Supply: Trusted by industries worldwide for reliable deliveries.
For further inquiries or to place an order, reach out to Mcneil Instruments today!